4a^2(4a^2-5/3b^2)+5/3b^2(4a^2-5/3b^2)

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Solution for 4a^2(4a^2-5/3b^2)+5/3b^2(4a^2-5/3b^2) equation: 


x in (-oo:+oo)

4*a^2*(4*a^2-((5/3)*b^2))+(5/3)*b^2*(4*a^2-((5/3)*b^2)) = 0

4*a^2*(4*a^2+(-5/3)*b^2)+(5/3)*b^2*(4*a^2+(-5/3)*b^2) = 0

4*a^2*(4*a^2-5/3*b^2)+5/3*b^2*(4*a^2-5/3*b^2) = 0

4*a^2*(4*a^2-5/3*b^2)+5/3*b^2*(4*a^2-5/3*b^2) = 0

16*a^4-25/9*b^4 = 0

16*a^4-25/9*b^4 = 0

x belongs to the empty set

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